(X+3)(x+4)=x^2-9

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Solution for (X+3)(x+4)=x^2-9 equation: 



(X+3)(X+4)=X^2-9

We move all terms to the left:

(X+3)(X+4)-(X^2-9)=0

We get rid of parentheses

-X^2+(X+3)(X+4)+9=0

We multiply parentheses ..

-X^2+(+X^2+4X+3X+12)+9=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+4X+3X+12)+9=0

We get rid of parentheses

-1X^2+X^2+4X+3X+12+9=0

We add all the numbers together, and all the variables

7X+21=0

We move all terms containing X to the left, all other terms to the right

7X=-21

X=-21/7

X=-3

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